
22ÄêÅÅÁÐÎå335ÆÚר¼Ò[Óο¡Îõ]Ô¤²âÏÂÆÚ±Ø³öºÅ

ÖйúÌå²ÊÖÐÐÄÅÅÁÐÎåÉÏÆÚ½±Âë->38350 ÅÅÁÐÈýÉÏÆÚ½±Âë->383
С´óС´óС£¬´óС±È2:3,012·±È3:0:2,ÆæÅ¼ÆæÆæÅ¼£¬ÖʺÏÖÊÖʺϣ¬ÖʺϱÈ3:2,ºÍÖµ19µã£¬ºÍβ9µã£¬¿ç¶È8¡£×î´óºÅ:8£¬×îСºÅ:0
[µÚһλ]ÉÏÆÚ¿ª³ö0·ºÅÂë3,ÀúÊ·½üÎåÆÚµÚһλ012·×ßÊÆÓɽü-Ô¶(0-2-1-2-2),±¾ÆÚµÚÒ»Î»ÍÆ¼ö0··ºÅÂëΪÖ÷·½Ïò£¬²Î¿¼ºÅÂë:0,2,3, ·ÀÓùºÅÂë1,8¡£
[µÚ¶þλ]ÉÏÆÚ¿ª³ö2·ºÅÂë8,ÀúÊ·½üÎåÆÚµÚ¶þλ012·×ßÊÆÓɽü-Ô¶(2-2-2-0-2),±¾ÆÚµÚ¶þÎ»ÍÆ¼ö1··ºÅÂëΪÖ÷·½Ïò£¬²Î¿¼ºÅÂë:1,2,6, ·ÀÓùºÅÂë7,9¡£
[µÚÈýλ]ÉÏÆÚ¿ª³ö0·ºÅÂë3,ÀúÊ·½üÎåÆÚµÚÈýλ012·×ßÊÆÓɽü-Ô¶(0-1-2-2-1),±¾ÆÚµÚÈýÎ»ÍÆ¼ö2··ºÅÂëΪÖ÷·½Ïò£¬²Î¿¼ºÅÂë:1,7,9, ·ÀÓùºÅÂë0,3¡£
[µÚËÄλ]ÉÏÆÚ¿ª³ö2·ºÅÂë5,ÀúÊ·½üÎåÆÚµÚËÄλ012·×ßÊÆÓɽü-Ô¶(2-0-2-0-1),±¾ÆÚµÚËÄÎ»ÍÆ¼ö0··ºÅÂëΪÖ÷·½Ïò£¬²Î¿¼ºÅÂë:2,3,9, ·ÀÓùºÅÂë1,6¡£
[µÚÎåλ]ÉÏÆÚ¿ª³ö0·ºÅÂë0,ÀúÊ·½üÎåÆÚµÚÎåλ012·×ßÊÆÓɽü-Ô¶(0-0-1-2-2),±¾ÆÚµÚÎåÎ»ÍÆ¼ö2··ºÅÂëΪÖ÷·½Ïò£¬²Î¿¼ºÅÂë:0,2,7, ·ÀÓùºÅÂë6,9¡£
ר¼Ò[Óο¡Îõ]Ô¤²âÅÅÁÐÎåÏÂÆÚ±Ø³öºÅ
µÚһλÎåÂë01238
µÚ¶þλÎåÂë12679
µÚÈýλÎåÂë01379
µÚËÄλÎåÂë12369
µÚÎåλÎåÂë02679
¾«Ñ¡Èý×¢:22006,39680,86623
µ¥ÌôÒ»×¢:39680
<¸öÈ˹۵ã,½ö¹©²Î¿¼>