
23ÄêÅÅÁÐÎå158ÆÚר¼Ò[Óο¡Îõ]Ô¤²âÏÂÆÚ±Ø³öºÅ

ÖйúÌå²ÊÖÐÐÄÅÅÁÐÎåÉÏÆÚ½±Âë->78642 ÅÅÁÐÈýÉÏÆÚ½±Âë->786
´ó´ó´óСС£¬´óС±È3:2,012·±È1:2:2,ÆæÅ¼Å¼Å¼Å¼£¬ÖʺϺϺÏÖÊ£¬ÖʺϱÈ2:3,ºÍÖµ27µã£¬ºÍβ7µã£¬¿ç¶È6¡£×î´óºÅ:8£¬×îСºÅ:2
[µÚһλ]ÉÏÆÚ¿ª³ö1·ºÅÂë7,ÀúÊ·½üÎåÆÚµÚһλ012·×ßÊÆÓɽü-Ô¶(1-2-2-1-1),±¾ÆÚµÚÒ»Î»ÍÆ¼ö1··ºÅÂëΪÖ÷·½Ïò£¬²Î¿¼ºÅÂë:3,7,8, ·ÀÓùºÅÂë4,5¡£
[µÚ¶þλ]ÉÏÆÚ¿ª³ö2·ºÅÂë8,ÀúÊ·½üÎåÆÚµÚ¶þλ012·×ßÊÆÓɽü-Ô¶(2-2-2-0-2),±¾ÆÚµÚ¶þÎ»ÍÆ¼ö0··ºÅÂëΪÖ÷·½Ïò£¬²Î¿¼ºÅÂë:0,3,4, ·ÀÓùºÅÂë1,2¡£
[µÚÈýλ]ÉÏÆÚ¿ª³ö0·ºÅÂë6,ÀúÊ·½üÎåÆÚµÚÈýλ012·×ßÊÆÓɽü-Ô¶(0-1-0-0-0),±¾ÆÚµÚÈýÎ»ÍÆ¼ö2··ºÅÂëΪÖ÷·½Ïò£¬²Î¿¼ºÅÂë:1,2,4, ·ÀÓùºÅÂë7,8¡£
[µÚËÄλ]ÉÏÆÚ¿ª³ö1·ºÅÂë4,ÀúÊ·½üÎåÆÚµÚËÄλ012·×ßÊÆÓɽü-Ô¶(1-2-2-2-0),±¾ÆÚµÚËÄÎ»ÍÆ¼ö1··ºÅÂëΪÖ÷·½Ïò£¬²Î¿¼ºÅÂë:1,3,7, ·ÀÓùºÅÂë0,4¡£
[µÚÎåλ]ÉÏÆÚ¿ª³ö2·ºÅÂë2,ÀúÊ·½üÎåÆÚµÚÎåλ012·×ßÊÆÓɽü-Ô¶(2-1-0-0-2),±¾ÆÚµÚÎåÎ»ÍÆ¼ö2··ºÅÂëΪÖ÷·½Ïò£¬²Î¿¼ºÅÂë:2,3,8, ·ÀÓùºÅÂë0,1¡£
ר¼Ò[Óο¡Îõ]Ô¤²âÅÅÁÐÎåÏÂÆÚ±Ø³öºÅ
µÚһλÎåÂë34578
µÚ¶þλÎåÂë01234
µÚÈýλÎåÂë12478
µÚËÄλÎåÂë01347
µÚÎåλÎåÂë01238
¾«Ñ¡Èý×¢:30259,43810,71849
µ¥ÌôÒ»×¢:43810
<¸öÈ˹۵ã,½ö¹©²Î¿¼>