
23ÄêÅÅÁÐÎå218ÆÚר¼Ò[Óο¡Îõ]Ô¤²âÏÂÆÚ±Ø³öºÅ

ÖйúÌå²ÊÖÐÐÄÅÅÁÐÎåÉÏÆÚ½±Âë->74883 ÅÅÁÐÈýÉÏÆÚ½±Âë->748
´óС´ó´óС£¬´óС±È3:2,012·±È1:2:2,ÆæÅ¼Å¼Å¼Ææ£¬ÖʺϺϺÏÖÊ£¬ÖʺϱÈ2:3,ºÍÖµ30µã£¬ºÍβ0µã£¬¿ç¶È5¡£×î´óºÅ:8£¬×îСºÅ:3
[µÚһλ]ÉÏÆÚ¿ª³ö1·ºÅÂë7,ÀúÊ·½üÎåÆÚµÚһλ012·×ßÊÆÓɽü-Ô¶(1-1-1-1-0),±¾ÆÚµÚÒ»Î»ÍÆ¼ö1··ºÅÂëΪÖ÷·½Ïò£¬²Î¿¼ºÅÂë:0,5,6, ·ÀÓùºÅÂë2,8¡£
[µÚ¶þλ]ÉÏÆÚ¿ª³ö1·ºÅÂë4,ÀúÊ·½üÎåÆÚµÚ¶þλ012·×ßÊÆÓɽü-Ô¶(1-0-2-0-1),±¾ÆÚµÚ¶þÎ»ÍÆ¼ö0··ºÅÂëΪÖ÷·½Ïò£¬²Î¿¼ºÅÂë:2,3,6, ·ÀÓùºÅÂë1,9¡£
[µÚÈýλ]ÉÏÆÚ¿ª³ö2·ºÅÂë8,ÀúÊ·½üÎåÆÚµÚÈýλ012·×ßÊÆÓɽü-Ô¶(2-2-0-1-1),±¾ÆÚµÚÈýÎ»ÍÆ¼ö2··ºÅÂëΪÖ÷·½Ïò£¬²Î¿¼ºÅÂë:1,2,9, ·ÀÓùºÅÂë0,5¡£
[µÚËÄλ]ÉÏÆÚ¿ª³ö2·ºÅÂë8,ÀúÊ·½üÎåÆÚµÚËÄλ012·×ßÊÆÓɽü-Ô¶(2-0-0-0-0),±¾ÆÚµÚËÄÎ»ÍÆ¼ö1··ºÅÂëΪÖ÷·½Ïò£¬²Î¿¼ºÅÂë:0,1,6, ·ÀÓùºÅÂë2,3¡£
[µÚÎåλ]ÉÏÆÚ¿ª³ö0·ºÅÂë3,ÀúÊ·½üÎåÆÚµÚÎåλ012·×ßÊÆÓɽü-Ô¶(0-1-2-0-2),±¾ÆÚµÚÎåÎ»ÍÆ¼ö2··ºÅÂëΪÖ÷·½Ïò£¬²Î¿¼ºÅÂë:5,6,9, ·ÀÓùºÅÂë1,3¡£
ר¼Ò[Óο¡Îõ]Ô¤²âÅÅÁÐÎåÏÂÆÚ±Ø³öºÅ
µÚһλÎåÂë02568
µÚ¶þλÎåÂë12369
µÚÈýλÎåÂë01259
µÚËÄλÎåÂë01236
µÚÎåλÎåÂë13569
¾«Ñ¡Èý×¢:20311,46770,72001
µ¥ÌôÒ»×¢:46770
<¸öÈ˹۵ã,½ö¹©²Î¿¼>


